So, either extract the year (=year(today()) or =year(now()) to get just the year) and display that as a number, or get the date via =today() or =now() and display that value as a custom date format of YYYY. What will not work is to get the year into the cell by =year(today()) and then use the “Numbers” tab | Category:Date | one of the mm/dd/yyyy formats because then the cell has the year but the formatting routine for displaying that cell’s value thinks the cell should be interpreted as if it had a date serial number, and 2013, for example, as July 5, 1905. For dates between the years 10, getFullYear () returns a four-digit number, for example, 2008. The value returned by getFullYear () is an absolute number. JavaScript date getFullYear () method returns the year of the specified date according to local time. If you just need to display the current date as a 4-digit year and you don’t care what the cell really contains, you can do the above to get the 4-digit year, or you can put the date in the cell (using =today(), or if you want to include seconds, =now() as the formula for the cell) and then format the cell to display as “Numbers” tab | Category:Date | Format: custom format code: YYYY (four upper-case Y’s). To get the current year, use the getFullYear () JavaScript method. Call the getFullYear () method on the Date object. (A cell that hasn’t been formatted has the formatting code of “Numbers” tab | Category:Number | Format:General.) To get the current year: Use the new Date () constructor to get a Date object. If you need the actual 4-digit year in the cell, and no other numbers in that cell, you can use either =year(today()) or =year(now()) as the formula in the cell, and make sure the format of the cell is either “Numbers” tab | Category:Number | Format:General or Format:-1234. Once you have a date object, you can apply any of the several available methods to extract its properties (e.g. Part of the answer depends on whether or not you are going to be feeding the year into some other calculation.
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